June 2019: Paper 2, Synthesis and analytical techniques

100 marks · 46 question parts · Paper, mark scheme and report on OCR's site · Have OCR's Data Sheet beside you

Question by question

QTopicMarksAOType
1 Alkanes 1AO1Multiple choice
2 Alkanes 1AO2Multiple choice
3 Organic basics: naming, formulae and isomerism 1AO1Multiple choice
4 Alkenes 1AO1Multiple choice
5 Alkenes, Alkanes 1AO2Multiple choice
6 Haloalkanes, Organic synthesis (Module 6) 1AO2Multiple choice
7 Amino acids, amides and chirality 1AO1Multiple choice
8 Aromatic compounds: benzene and phenol 1AO1Multiple choice
9 Polyesters and polyamides 1AO2Multiple choice
10 NMR spectroscopy and combined techniques 1AO2Multiple choice
11 Amount of substance (moles) 1AO2Multiple choice
12 NMR spectroscopy and combined techniques 1AO2Multiple choice
13 Carbonyl compounds: aldehydes and ketones, Alcohols 1AO1Multiple choice
14 Aromatic compounds: benzene and phenol, Carboxylic acids, esters and acyl chlorides 1AO1Multiple choice
15 Organic synthesis (Module 6), Amino acids, amides and chirality 1AO1Multiple choice
16(a)(i) Alkenes, Organic basics: naming, formulae and isomerism 4AO1, 2Mechanism
16(a)(ii) Alkenes 2AO1Short answer
16(b)(i) Carbonyl compounds: aldehydes and ketones, Chromatography and tests for functional groups 2AO1Short answer
16(b)(ii) Amount of substance (moles), Organic basics: naming, formulae and isomerism 1AO1Short answer
16(b)(iii) Organic basics: naming, formulae and isomerism 1AO1Short answer
16(b)(iv) Alkenes 1AO1Short answer
16(b)(v) Alkenes, Amino acids, amides and chirality 4AO1, 2Structure / isomer
17(a)(i) Amino acids, amides and chirality, Carboxylic acids, esters and acyl chlorides, Organic synthesis (Module 6) 4AO2Drawing / labelling
17(a)(ii) Acids, bases and titrations, Amount of substance (moles), Amino acids, amides and chirality 4AO2, 3Data interpretation
17(b)(i) Chromatography and tests for functional groups 1AO1Calculation
17(b)(ii) Chromatography and tests for functional groups 2AO2Data interpretation
18(a)(i) Organic basics: naming, formulae and isomerism 1AO1Short answer
18(a)(ii) Carboxylic acids, esters and acyl chlorides, Haloalkanes, Organic synthesis (Module 6) 5AO2Drawing / labelling
18(a)(iii) Carboxylic acids, esters and acyl chlorides 1AO1Short answer
18(b) NMR spectroscopy and combined techniques 4AO3Complete table/diagram
18(c) NMR spectroscopy and combined techniques, Organic basics: naming, formulae and isomerism, Carboxylic acids, esters and acyl chlorides, Chromatography and tests for functional groups 1AO3Structure / isomer
18(d) Polyesters and polyamides, Atomic structure and isotopes 2AO2Calculation
18(e)(i) Organic synthesis (Module 6), Amount of substance (moles), Carbonyl compounds: aldehydes and ketones, Carboxylic acids, esters and acyl chlorides 6AO3Level of response
18(e)(ii) Infrared spectroscopy and mass spectrometry 2AO2Short answer
19(a)(i) Aromatic compounds: benzene and phenol 3AO1Short answer
19(a)(ii) Aromatic compounds: benzene and phenol 2AO1Short answer
19(b)(i) Polyesters and polyamides, Alkenes 3AO1, 2Drawing / labelling
19(b)(ii) Polyesters and polyamides 1AO1Short answer
19(b)(iii) Aromatic compounds: benzene and phenol, Organic basics: naming, formulae and isomerism, Carbon–carbon bond formation 5AO1, 2, 3Mechanism
19(b)(iv) Organic synthesis (Module 6), Alcohols, Carbonyl compounds: aldehydes and ketones, Amines, Carbon–carbon bond formation 7AO2Short answer
20(a)(i) Organic basics: naming, formulae and isomerism 1AO1Short answer
20(a)(ii) Organic basics: naming, formulae and isomerism 2AO3Mechanism
20(a)(iii) Organic basics: naming, formulae and isomerism 2AO1Data interpretation
20(b)(i) Organic basics: naming, formulae and isomerism, Carboxylic acids, esters and acyl chlorides 4AO3Mechanism
20(b)(ii) Haloalkanes 1AO1Short answer
21 Amount of substance (moles), Infrared spectroscopy and mass spectrometry, NMR spectroscopy and combined techniques 6Level of response

The questions

12345678910111213141516(a)(i)16(a)(ii)16(b)(i)16(b)(ii)16(b)(iii)16(b)(iv)16(b)(v)17(a)(i)17(a)(ii)17(b)(i)17(b)(ii)18(a)(i)18(a)(ii)18(a)(iii)18(b)18(c)18(d)18(e)(i)18(e)(ii)19(a)(i)19(a)(ii)19(b)(i)19(b)(ii)19(b)(iii)19(b)(iv)20(a)(i)20(a)(ii)20(a)(iii)20(b)(i)20(b)(ii)21
June 2019 · Paper 2 · Q1 1 mark AO1 Multiple choice alkanes
1 Which alkane has the highest boiling point?
A CH3(CH2)5CH3
B (CH3)3CCH(CH3)2
C CH3(CH2)3CH(CH3)2
D (CH3)2CHCH2CH(CH3)2
Your answer
[1]
June 2019 · Paper 2 · Q2 1 mark AO2 Multiple choice alkanes
2 Butane reacts with chlorine in the presence of ultraviolet radiation to form a mixture of organic
products.
Which equation shows a propagation step in the mechanism for this reaction?
A Cl 2  →  •Cl  + •Cl
B •Cl  + •C4H8Cl   →  C4H8Cl 2
C C4H9Cl  + •Cl  →  C4H8Cl 2 + •H
D •Cl  + C4H9Cl  →  •C4H8Cl  + HCl
Your answer
[1]
June 2019 · Paper 2 · Q3 1 mark AO1 Multiple choice Medium organic basics
3 What is the name of the compound below?
H CH3
C
C
H3C CH2 CH2 CH2 CH3
A 3-Propylpent-2-ene
B 3-Propylpent-3-ene
C 3-Ethylhex-2-ene
D 4-Ethylhex-4-ene
Your answer
[1]
June 2019 · Paper 2 · Q4 1 mark AO1 Multiple choice Hard alkenes
4 The structure of a stereoisomer is shown below.
H3C CH(CH3)2
C C
CH3CH2 CH2CH2CH3
Which term correctly describes this stereoisomer?
A cis-
B trans-
C E-
D Z-
Your answer
[1]
June 2019 · Paper 2 · Q5 1 mark AO2 Multiple choice Medium alkenesalkanes
5 Which types of bonds are broken and formed in the reaction of ethene and bromine?
Types of bond broken Types of bond formed
A σ π
B π σ
C σ and π π
D σ and π σ
Your answer
[1]
June 2019 · Paper 2 · Q6 1 mark AO2 Multiple choice haloalkanesorganic synthesis
6 What is the organic product of the reaction below?
CH2Cl
KOH(aq)
Cl
CH2OH
A
Cl
CH2Cl
B
OH
CH2OH
C
OH
HO CH2Cl
D
Cl
Your answer
[1]
June 2019 · Paper 2 · Q7 1 mark AO1 Multiple choice amino acids amides and chirality
7 What is the number of chiral carbon atoms in the steroid molecule below?
OH
O
A 5
B 6
C 7
D 8
Your answer
[1]
June 2019 · Paper 2 · Q8 1 mark AO1 Multiple choice aromatic compounds
8 Phenol reacts with bromine.
Which is the least likely organic product?
OH
Br
A
Br
OH
Br Br
B
OH
Br
C
Br
OH
Br Br
D
Br
Your answer
[1]
June 2019 · Paper 2 · Q9 1 mark AO2 Multiple choice condensation polymers
9 The repeat unit of a polymer is shown below.
H H H H O
O C C O C C C C
H H O H H
Which monomers could form this polymer?
O
OH HO
A
HO OH
O
O
OH
HO OH
B
HO
O
O O
HO OH
C
HO OH
O O
D
HO
HO OH OH
Your answer
[1]
June 2019 · Paper 2 · Q10 1 mark AO2 Multiple choice Easy nmr spectroscopy
10 Which compound shows 4 peaks in its carbon-13 NMR spectrum?
A
B
C
D
Your answer
[1]
June 2019 · Paper 2 · Q11 1 mark AO2 Multiple choice amount of substance
11 A student reacts 4.50 g of C6H5NH2 with excess CH3COCl  in the reaction below.
C6H5NH2 + CH3COCl  → C6H5NHCOCH3 + HCl
Mr = 93.0           Mr = 135.0
The reaction produces 3.25 g of C6H5NHCOCH3.
What is the percentage yield of C6H5NHCOCH3?
A 49.8
B 68.9
C 72.2
D 95.4
Your answer
[1]
June 2019 · Paper 2 · Q12 1 mark AO2 Multiple choice Medium nmr spectroscopy
12 A compound produces the 13C NMR spectrum below.
80 70 60 50 40 30 20 10 0
chemical shift, d / ppm
Which compound could have produced this spectrum?
A Propane
B 2-Methylbutane
C 2-Methylpropan-1-ol
D 2-Methylpropan-2-ol
Your answer
[1]
June 2019 · Paper 2 · Q13 1 mark AO1 Multiple choice Hard carbonyl compoundsalcohols
13 A carbonyl compound is reacted with NaBH4.
Which compound(s) could be formed?
1 2-Methylpentan-2-ol
2 2-Methylpentan-1-ol
3 3-Methylpentan-2-ol
A 1, 2 and 3
B Only 1 and 2
C Only 2 and 3
D Only 1
Your answer
[1]
June 2019 · Paper 2 · Q14 1 mark AO1 Multiple choice Hard aromatic compoundscarboxylic acids and esters
14 Which chemical(s) can react with phenol?
1 Potassium hydroxide
2 Ethanoyl chloride
3 Nitric acid
A 1, 2 and 3
B Only 1 and 2
C Only 2 and 3
D Only 1
Your answer
[1]
June 2019 · Paper 2 · Q15 1 mark AO1 Multiple choice Easy organic synthesisamino acids amides and chirality
15 The structure of a compound used to treat influenza is shown below.
O
O
O
HN
NH2
O
Which functional group(s) is/are in a molecule of the compound?
1 Ester
2 Secondary amide
3 Ketone
A 1, 2 and 3
B Only 1 and 2
C Only 2 and 3
D Only 1
Your answer
[1]
June 2019 · Paper 2 · Q16(a)(i) 4 marks AO1, 2 Mechanism Easy alkenesorganic basics
SECTION B
Answer all the questions.
16 This question is about unsaturated aldehydes and alcohols.
(a) 3-Methylbut-2-enal, shown below, is used as a food flavouring.
H3C CHO
C C
H3C H
3-methylbut-2-enal
3-Methylbut-2-enal is reacted with hydrogen bromide, forming a mixture of two organic
products.
One of the organic products forms in a much greater quantity than the other organic product.
(i) Outline the reaction mechanism for the formation of one of the organic products.
Include curly arrows and relevant dipoles.
[4]
June 2019 · Paper 2 · Q16(a)(ii) 2 marks AO1 Short answer Medium alkenes
Earlier part of question 16 that this part usesEarlier part of June 2019 Paper 2 question 16
(ii) Explain why one of the organic products forms in a much greater quantity than the other
organic product.
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June 2019 · Paper 2 · Q16(b)(i) 2 marks AO1 Short answer Easy carbonyl compoundschromatography and functional group tests
(b) Geraniol and citronellal, shown below, are isomers present in ‘citronella oil’, used as an insect
repellent.
OH
O
Geraniol Citronellal
• Geraniol and citronellal are structural isomers of each other.
• They also show stereoisomerism.
(i) Describe how the observations from a chemical test would distinguish between geraniol
and citronellal.
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June 2019 · Paper 2 · Q16(b)(ii) 1 mark AO1 Short answer Medium amount of substanceorganic basics
Earlier part of question 16 that this part usesEarlier part of June 2019 Paper 2 question 16
(ii) What is the molecular formula of geraniol?
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June 2019 · Paper 2 · Q16(b)(iii) 1 mark AO1 Short answer Medium organic basics
Earlier parts of question 16 that this part usesEarlier part of June 2019 Paper 2 question 16Earlier part of June 2019 Paper 2 question 16
(iii) Explain why geraniol and citronellal are structural isomers of each other.
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June 2019 · Paper 2 · Q16(b)(iv) 1 mark AO1 Short answer Easy alkenes
Earlier part of question 16 that this part usesEarlier part of June 2019 Paper 2 question 16
(iv) Explain the term stereoisomerism.
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June 2019 · Paper 2 · Q16(b)(v) 4 marks AO1, 2 Structure / isomer Hard alkenesamino acids amides and chirality
Earlier part of question 16 that this part usesEarlier part of June 2019 Paper 2 question 16
(v) The structures of geraniol and citronellal are repeated below with the carbon atoms
numbered.
7 1 1
7
5 4 3 5 4 3 2
8 OH 8
6 2 6 O
Geraniol Citronellal
Explain the types of stereoisomerism shown by geraniol and citronellal.
In your answer,
• refer to the numbered carbon atoms in the structures above
• draw diagrams clearly showing any stereoisomers.
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Geraniol stereoisomers
Citronellal stereoisomers
[4]
June 2019 · Paper 2 · Q17(a)(i) 4 marks AO2 Drawing / labelling Medium amino acids amides and chiralitycarboxylic acids and estersorganic synthesis
17 This question is about α-amino acids, RCH(NH2)COOH.
(a) Table 17.1 shows the R groups in four amino acids.
Amino acid R group
alanine (ala) CH3–
serine (ser) HOCH2–
leucine (leu) (CH3)2CHCH2–
glycine (gly) H–
Table 17.1
(i) In the boxes, draw the organic products for the reactions of serine shown below.
(CH3)2CHOH / H2SO4
H+(aq)
H
O
excess CH3COCl
H2N C C
OH
CH2
OH
serine
[4]
June 2019 · Paper 2 · Q17(a)(ii) 4 marks AO2, 3 Data interpretation Easy acids and titrationsamount of substanceamino acids amides and chirality
Earlier part of question 17 that this part usesEarlier part of June 2019 Paper 2 question 17
(ii) A student is provided with one of the four amino acids in Table 17.1.
A student carries out a titration with a standard solution of hydrochloric acid to identify
the amino acid. The student’s method is outlined below.
• The student dissolves 5.766 g of the amino acid in water and makes the solution up
to 250.0 cm3 in a volumetric flask.
• The student titrates this solution with 25.0 cm3 of 0.150 mol dm−3 hydrochloric acid.
• 21.30 cm3 of the amino acid solution were required for complete neutralisation of the
hydrochloric acid.
Determine which amino acid the student used.
[4]
June 2019 · Paper 2 · Q17(b)(i) 1 mark AO1 Calculation Easy chromatography and functional group tests
Earlier part of question 17 that this part usesEarlier part of June 2019 Paper 2 question 17
(b) The student is provided with another amino acid.
The student attempts to identify the unknown amino acid using chromatography.
The student obtains two TLC chromatograms of the unknown amino acid and the four amino
acids in Table 17.1, using two different solvents, W and X.
solvent  front
origin
unknown ala ser leu gly unknown ala ser leu gly
amino amino
acid acid
Solvent W Solvent X
(i) What is the Rf value of serine (ser) in solvent W?
Rf =  ......................................................... [1]
June 2019 · Paper 2 · Q17(b)(ii) 2 marks AO2 Data interpretation Easy chromatography and functional group tests
Earlier parts of question 17 that this part usesEarlier part of June 2019 Paper 2 question 17Earlier part of June 2019 Paper 2 question 17
(ii) Analyse the chromatograms to identify the unknown amino acid.
Explain your reasoning.
Name of unknown amino acid  ...........................................................................................
Explanation  .......................................................................................................................
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June 2019 · Paper 2 · Q18(a)(i) 1 mark AO1 Short answer Hard organic basics
18 This question is about esters.
(a) The structure of ester A is shown below.
O
Br O
Ester A
(i) What is the systematic name of ester A?
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June 2019 · Paper 2 · Q18(a)(ii) 5 marks AO2 Drawing / labelling Medium carboxylic acids and estershaloalkanesorganic synthesis
Earlier part of question 18 that this part usesEarlier part of June 2019 Paper 2 question 18
(ii) In the boxes, draw the organic products for the reactions of the functional groups in
ester A shown below.
Each reaction forms two organic products.
+
H+(aq)
O
Br O
Ester A
excess OH–(aq)
+
[5]
June 2019 · Paper 2 · Q18(a)(iii) 1 mark AO1 Short answer Hard carboxylic acids and esters
Earlier parts of question 18 that this part usesEarlier part of June 2019 Paper 2 question 18Earlier part of June 2019 Paper 2 question 18
(iii) Name the type of reactions of ester A shown in (ii).
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June 2019 · Paper 2 · Q18(b) 4 marks AO3 Complete table/diagram Easy nmr spectroscopy
Earlier part of question 18 that this part usesEarlier part of June 2019 Paper 2 question 18
(b) The protons in ester A are in four different environments, labelled 1– 4 on the structure below.
1 O 3
4
CH2 C CH2
Br CH2 O CH3
2
Complete the table to predict the proton NMR spectrum of ester A.
Proton environment Chemical shift Splitting pattern
1
2
3
4
[4]
June 2019 · Paper 2 · Q18(c) 1 mark AO3 Structure / isomer Medium nmr spectroscopyorganic basicscarboxylic acids and esterschromatography and functional group tests
Earlier part of question 18 that this part usesEarlier part of June 2019 Paper 2 question 18
(c) Compound B is a structural isomer of ester A.
• Compound B reacts with aqueous sodium carbonate.
• The 13C NMR spectrum of B has 4 peaks.
Draw a possible structure for compound B.
[1]
June 2019 · Paper 2 · Q18(d) 2 marks AO2 Calculation Medium condensation polymersatomic structure and isotopes
(d) A polyester is formed from 200 molecules of 4-hydroxybenzoic acid.
What is the relative molecular mass, Mr, of the polyester?
Mr =  ............................................. g mol−1 [2]
June 2019 · Paper 2 · Q18(e)(i) 6 marks AO3 6-mark level of response Medium organic synthesisamount of substancecarbonyl compoundscarboxylic acids and esters
(e)* A student intends to synthesise ester C.
H
O
H3C C C
O CH3
CH3
Ester C
(i) Plan a two-stage synthesis to prepare 12.75 g of ester C starting from 2-methylpropanal,
(CH3)2CHCHO. Assume the overall percentage yield of ester C from 2-methylpropanal is
40%.
In your answer include the mass of 2-methylpropanal required, reagents, conditions and
equations where appropriate.
Purification details are not required. [6]
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June 2019 · Paper 2 · Q18(e)(ii) 2 marks AO2 Short answer Easy infrared and mass spectrometry
Earlier part of question 18 that this part usesEarlier part of June 2019 Paper 2 question 18
(ii) The mass spectrum of ester C is shown below.
100
Y
80
60
Relative
intensity
40
Z
20
0
10 20 30 40 50 60 70 80 90 100
m / z
Suggest possible structures for the species responsible for peaks Y and Z in the mass
spectrum.
Y Z
[2]
June 2019 · Paper 2 · Q19(a)(i) 3 marks AO1 Short answer Hard aromatic compounds
19 This question is about benzene.
(a) Over time, the Kekulé and delocalised models have been used to describe the bonding and
structure of a benzene molecule.
(i) Describe, in terms of orbital overlap, the similarities and differences between the bonding
in the Kekulé model and the delocalised model of benzene.
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June 2019 · Paper 2 · Q19(a)(ii) 2 marks AO1 Short answer Medium aromatic compounds
Earlier part of question 19 that this part usesEarlier part of June 2019 Paper 2 question 19
(ii) Experimental evidence led to the general acceptance of the delocalised model over the
Kekulé model.
Describe two pieces of evidence to support the delocalised model of benzene.
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June 2019 · Paper 2 · Q19(b)(i) 3 marks AO1, 2 Drawing / labelling Medium condensation polymersalkenes
(b) Benzene can be used as the starting material for the synthesis of compounds D and E, shown
below.
In the diagrams C6H5 is a phenyl group.
CH3
H H
C C H2N C COOH
C6H5 H
C6H5
compound D compound E
Compounds D and E can be converted into polymers.
(i) Draw two repeat units of these polymers.
Two repeat units of polymer formed from D
Two repeat units of polymer formed from E
[3]
June 2019 · Paper 2 · Q19(b)(ii) 1 mark AO1 Short answer Hard condensation polymers
Earlier part of question 19 that this part usesEarlier part of June 2019 Paper 2 question 19
(ii) State the type of polymer formed from compounds D and E.
From compound D  ............................................................................................................
From compound E  .............................................................................................................
[1]
June 2019 · Paper 2 · Q19(b)(iii) 5 marks AO1, 2, 3 Mechanism Medium aromatic compoundsorganic basicscarbon carbon bond formation
Earlier part of question 19 that this part usesEarlier part of June 2019 Paper 2 question 19
(iii) In the synthesis of compounds D and E, benzene is first reacted with ethanoyl chloride,
CH3COCl, to form phenylethanone, shown below.
H3C O
C
phenylethanone
The reaction takes place in the presence of aluminium chloride, Al Cl 3, which acts as a
catalyst.
In the mechanism for this reaction,
• ethanoyl chloride first reacts with aluminium chloride to form the CH3–C+=O cation
• the CH3–C+=O cation then behaves as an electrophile.
Complete the mechanism for the reaction.
Include equations to show the role of the Al Cl 3 catalyst, relevant curly arrows and the
structure of the intermediate.
Formation of electrophile  ...................................................................................................
+
H3C C O
Intermediate
H3C O
C
+ H+
Regeneration of catalyst  ...................................................................................................
[5]
June 2019 · Paper 2 · Q19(b)(iv) 7 marks AO2 Short answer Hard organic synthesisalcoholscarbonyl compoundsaminescarbon carbon bond formation
Earlier parts of question 19 that this part usesEarlier part of June 2019 Paper 2 question 19Earlier part of June 2019 Paper 2 question 19
(iv) Complete the flowchart for the synthesis of compounds D and E from phenylethanone.
H3C O
C
NaBH4
phenylethanone
NaCN(aq) / H+(aq)
..................................................
H
H C
H
C
..................................................
CH3
compound D
Br C CN
..................................................
CH3
H2N C COOH
....................................
compound E [7]
June 2019 · Paper 2 · Q20(a)(i) 1 mark AO1 Short answer Easy organic basics
20 This question is about reaction mechanisms.
(a) Chemists use curly arrows in reaction mechanisms.
(i) What does a curly arrow show in a reaction mechanism?
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June 2019 · Paper 2 · Q20(a)(ii) 2 marks AO3 Mechanism Medium organic basics
Earlier part of question 20 that this part usesEarlier part of June 2019 Paper 2 question 20
(ii) Draw structures to show the products in the reaction mechanism below.
H H
+
O
[2]
June 2019 · Paper 2 · Q20(a)(iii) 2 marks AO1 Data interpretation Medium organic basics
Earlier part of question 20 that this part usesEarlier part of June 2019 Paper 2 question 20
(iii) Use the mechanism in (ii) to explain what is meant by heterolytic fission.
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June 2019 · Paper 2 · Q20(b)(i) 4 marks AO3 Mechanism Medium organic basicscarboxylic acids and esters
Earlier part of question 20 that this part usesEarlier part of June 2019 Paper 2 question 20
(b) An incomplete reaction mechanism is shown below.
(i) Complete the mechanism by adding curly arrows and any missing species.
–
O O
H3C C H3C C Cl
Cl
OH
–
OH
O
H3C C + …………
OH
[4]
June 2019 · Paper 2 · Q20(b)(ii) 1 mark AO1 Short answer Medium haloalkanes
Earlier part of question 20 that this part usesEarlier part of June 2019 Paper 2 question 20
(ii) What is the role of OH− in this mechanism?
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June 2019 · Paper 2 · Q21 6 marks 6-mark level of response Medium amount of substanceinfrared and mass spectrometrynmr spectroscopy
21* Analysis of an unknown organic compound produced the following results.
Elemental analysis by mass
C: 73.17%; H: 7.32%; O: 19.51%
Mass spectrum
Molecular ion peak at m / z = 164.0
Infrared spectrum
100
Transmittance
(%) 50
0
4000 3000 2000 1500 1000 500
Wavenumber / cm–1
1H NMR spectrum in D2O
3
4 3
1
8 7 6 5 4 3 2 1 0
Chemical shift, d / ppm
The numbers by the peaks are the relative peak areas.
Use the results to suggest one possible structure for the unknown compound.
Show all your reasoning. [6]
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